inputstandard input

outputstandard output

You are given a string s consisting only of characters 0 and 1. A substring [l, r] of s is a string slsl + 1sl + 2… sr, and its length equals to r - l + 1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.

You have to determine the length of the longest balanced substring of s.

Input

The first line contains n (1 ≤ n ≤ 100000) — the number of characters in s.

The second line contains a string s consisting of exactly n characters. Only characters 0 and 1 can appear in s.

Output

If there is no non-empty balanced substring in s, print 0. Otherwise, print the length of the longest balanced substring.

Examples

input

8

11010111

output

4

input

3

111

output

0

Note

In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.

In the second example it’s impossible to find a non-empty balanced substring.

题意

给你一串01串，让你找到最大的[l,r]使得0和1的数量相等

题解

我们知道01数量想等，那么和肯定为0，然后我们把0变成-1

题目就转变成求最长子序列使[l,r]总和为0

代码

1 #include
     
       2 using namespace std; 3  4 const int N=1e5+5; 5 int n,sum,ans; 6 char s[N]; 7 unordered_map
      
       S; 8 int main() 9 {10     scanf("%d%s",&n,s+1);S[0]=0;11     for(int i=1;i<=n;i++)12     {13         sum+=(s[i]=='1'?1:-1);14         if(S.count(sum))ans=max(ans,i-S[sum]);15         else S[sum]=i;16     }17     printf("%d",ans);18     return 0;19 }